Fundamentals in solving equations in one or more steps

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When we want to solve an equation including one unknown variable, as x in the example above, we always aim at isolating the unknown variable. Algebra1/ Howtosolvelinearequations/ Fundamentalsinsolvingequationsinoneormoresteps Formulasareverycommonwithinphysicsandchemistry,forexample,velocityequalsdistancedividedbytime.Thusweusethecommonsymbolsforvelocity(v),distance(d)andtime(t)andexpressitthus: $$v=\frac{d}{t}$$ Wemaysimplydescribeaformulaasbeingavariableandanexpressionseparatedbyanequalsignbetweenthem.Inotherwordsaformulaisthesameasanequation. Example Abookclubrequiresamembershipfeeof$10inadditiontothe$2leviedforeachbookordered.Ifweweretolistthecostoforderinganumberofbooks,itwouldlooklike: Numberofbooks Cost 1 10+2∙1=12 2 10+2∙2=14 3 10+2∙3=16 4 10+2∙4=18 5 10+2∙5=20 x 10+2x IfwedesignatethetotalbookclubcostasC,wemayderivethefollowingformulafortheexpression: $$C=10+2x$$ Ifwethenwanttoknowhowmanybookswemaygetfromthebookclubfor$30wecaneithercontinuefillinginthetableaboveorusethepropertiesofequationsthatwehandledinthelastsection. $$30=10+2x$$ Cwasthecost,i.e.itisnow$30 $$30\:{\color{green}{-\,10}}=10+2x\,{\color{green}{-\,10}}$$ wesubtract$10fromeachside $$20=2x$$ simplify $$\frac{20}{{\color{green}2}}=\frac{2x}{{\color{green}2}}$$ dividebothsidesby2toisolatex $$10=x$$ xequals10 Wemaypurchase10booksfor$30. Whenwewanttosolveanequationincludingoneunknownvariable,asxintheexampleabove,wealwaysaimatisolatingtheunknownvariable.Youcansaythatweputeverythingelseontheothersideoftheequalsign.Itisalwaysagoodideatofirstisolatethetermsincludingthevariablefromtheconstantstobeginwithaswedidabovebysubtractingoraddingbeforedividingormultiplyingawaythecoefficientinfrontofthevariable.Aslongasyoudothesamethingonbothsidesoftheequalsignyoucandowhateveryouwantandinwhichorderyouwant. Abovewebeganbysubtractingtheconstantonbothsides.Wecouldhavebegunbydividingby2instead.Itwouldhavelookedlike $$\frac{30}{{\color{blue}2}}=\frac{10+2x}{{\color{blue}2}}$$ $$\frac{30}{{\color{blue}2}}=\frac{10}{{\color{blue}2}}+\frac{2x}{{\color{blue}2}}$$ $$15=5+x$$ $$15\,{\color{blue}{-\,5}}=5+x\,{\color{blue}{-\,5}}$$ $$10=x$$ Againthesameanswerjustprovingthepoint. Ifyourequationcontainsliketermsitispreferabletobeginbycombiningtheliketermsbeforecontinuingsolvingtheequation. Example $$5x+14+2x+2=30$$ Beginbycombiningtheliketerms(alltermsincludingthesamevariablexandallconstants) $$\left(5x+2x\right)+\left(14+2\right)=30$$ $$7x+16=30$$ Nowit'stimetoisolatethevariablefromtheconstantpart.Thisisdonebysubtracting16frombothsides $$7x+16\,{\color{green}{-\,16}}=30\,{\color{green}{-\,16}}$$ $$7x=14$$ Dividebothsidesby7toisolatethevariable $$\frac{7x}{{\color{green}7}}=\frac{14}{{\color{green}7}}$$ $$x=2$$ Ifyouhaveanequationwhereyouhavevariablesonbothsidesyoudobasicallythesamethingasbefore.Youcollectallliketerms.Beforeyouhaveworkedbyfirstcollectingallconstanttermsononesideandkeepthevariabletermsontheotherside.Thesameapplieshere.Youcollectallconstanttermsononesideandthevariabletermsontheotherside.It'susuallyagoodideatocollectallvariablesonthesidethathasthevariablewiththehighestcoefficienti.e.intheexamplebelowtherearemorex:esontheleftside(4x)comparedtotherightside(2x)andhencewecollectallx:esontheleftside. Example $$4x+3=2x+11$$ subtract2xfrombothsides $$4x+3\,{\color{blue}{-\,2x}}=2x+11\,{\color{blue}{-\,2x}}$$ Nowitlookslikeanyotherequation $$2x+3=11$$ subtract3frombothsides $$2x+3\,{\color{blue}{-\,3}}=11\,{\color{blue}{-\,3}}$$ $$2x=8$$ Divideby2onbothsides $$\frac{2x}{{\color{blue}2}}=\frac{8}{{\color{blue}2}}$$ $$x=4$$ Inthebeginningofthissectionweshowedtheformulaforcalculatingthevelocitywherevelocity(v)equalsthedistance(d)dividedbytime(t)or $$v=\frac{d}{t}$$ Ifwebysomechancewanttoknowhowfaratruckdrivesin3hoursat60milesperhourwecanusetheformulaaboveandrewriteittosolvethedistance,d. $$\frac{d}{t}\,{\color{green}{\cdot\,t}}=v\,{\color{green}{\cdot\,t}}$$ $$d=v\cdott$$ Whenthat'sdonewecanjustputournumbersintheformulaandcalculatetheanswer $$d=60\cdot3=180$$ Thetrucktravels180milesin3hours. Thisholdstrueforallformulasandequations. 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